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template-glib 3.38.0-2
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# Italian translation for template-glib.
# Copyright (C) 2018 Free Software Foundation, Inc.
# This file is distributed under the same license as the template-glib package.
# Milo Casagrande <milo@milo.name>, 2018.
#
msgid ""
msgstr ""
"Project-Id-Version: template-glib template-glib-3-28\n"
"Report-Msgid-Bugs-To: https://gitlab.gnome.org/GNOME/template-glib/issues\n"
"POT-Creation-Date: 2018-03-14 17:03+0000\n"
"PO-Revision-Date: 2018-11-21 14:20+0100\n"
"Language-Team: Italian <gnome-it-list@gnome.org>\n"
"Language: it\n"
"MIME-Version: 1.0\n"
"Content-Type: text/plain; charset=UTF-8\n"
"Content-Transfer-Encoding: 8bit\n"
"Plural-Forms: nplurals=2; plural=(n != 1);\n"
"Last-Translator: Milo Casagrande <milo@milo.name>\n"
"X-Generator: Poedit 2.1.1\n"

#: src/tmpl-parser.c:199
#, c-format
msgid "%s() may only be called once"
msgstr "%s() può essere chiamata solo una volta"

#: src/tmpl-parser.c:211
#, c-format
msgid "Parser does not contain an input stream"
msgstr "L'analizzatore non contiene uno stream di input"

#: src/tmpl-template.c:454
#, c-format
msgid "Must parse template before expanding"
msgstr "Necessario analizzare il modello prima dell'espansione"

#: src/tmpl-template-locator.c:117
#, c-format
msgid "Failed to locate template “%s”"
msgstr "Impossibile trovare il modello «%s»"