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CN106847325A - Primary particle inversion resistant memory cell - Google Patents

Primary particle inversion resistant memory cell Download PDF

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Publication number
CN106847325A
CN106847325A CN201611218768.1A CN201611218768A CN106847325A CN 106847325 A CN106847325 A CN 106847325A CN 201611218768 A CN201611218768 A CN 201611218768A CN 106847325 A CN106847325 A CN 106847325A
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transistor
node
level
memory cell
grid
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郭靖
朱磊
董亮
刘文怡
熊继军
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North University of China
Qiqihar University
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North University of China
Qiqihar University
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    • GPHYSICS
    • G11INFORMATION STORAGE
    • G11CSTATIC STORES
    • G11C7/00Arrangements for writing information into, or reading information out from, a digital store
    • G11C7/24Memory cell safety or protection circuits, e.g. arrangements for preventing inadvertent reading or writing; Status cells; Test cells
    • HELECTRICITY
    • H03ELECTRONIC CIRCUITRY
    • H03KPULSE TECHNIQUE
    • H03K19/00Logic circuits, i.e. having at least two inputs acting on one output; Inverting circuits
    • H03K19/003Modifications for increasing the reliability for protection
    • H03K19/0033Radiation hardening
    • H03K19/00338In field effect transistor circuits

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  • Engineering & Computer Science (AREA)
  • Computer Hardware Design (AREA)
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Abstract

抗单粒子翻转的存储单元,涉及集成电路抗辐射加固领域。解决了辐射粒子使得存储器存储的信息翻转,从而降低存储器可靠性的问题。本发明由10个MOS管来组成,分别是PMOS晶体管P1、P2以及NMOS晶体管N1、N2、N3、N4、N5、N6、N7和N8。本发明可以对存储单元中任意单个节点的翻转进行加固,还可以对固定的两个节点进行抗多节点翻转容错,而同时不依赖于所存储的值。本发明主要用于对存储器进行抗单粒子翻转的加固保护。

The invention relates to a single-event flip-resistant storage unit, which relates to the field of anti-radiation hardening of integrated circuits. Solved the problem that radiation particles flipped the information stored in the memory, thereby reducing the reliability of the memory. The present invention consists of 10 MOS transistors, which are respectively PMOS transistors P1 and P2 and NMOS transistors N1, N2, N3, N4, N5, N6, N7 and N8. The present invention can strengthen the flipping of any single node in the storage unit, and can also implement anti-multi-node flipping and fault tolerance for two fixed nodes without depending on the stored value at the same time. The invention is mainly used for strengthening and protecting the memory against single event reversal.

Description

抗单粒子翻转的存储单元Memory cell resistant to single event upset

技术领域technical field

本发明涉及集成电路抗辐射加固领域。The invention relates to the field of anti-radiation hardening of integrated circuits.

背景技术Background technique

随着半导体技术的不断发展,自然界和宇宙环境中的辐射粒子将更容易使得存储器存储的信息翻转,导致单粒子翻转的发生,从而降低存储器的可靠性。因此,在现代集成电路存储器的设计中,需要对其进行抗单粒子翻转的加固保护。With the continuous development of semiconductor technology, radiation particles in the natural and cosmic environment will more easily flip the information stored in the memory, resulting in the occurrence of single event flipping, thereby reducing the reliability of the memory. Therefore, in the design of modern integrated circuit memory, it needs to be protected against single event upset.

发明内容Contents of the invention

本发明是为了解决辐射粒子使得存储器存储的信息翻转,从而降低存储器可靠性的问题,本发明提供了一种抗单粒子翻转的存储单元。The purpose of the present invention is to solve the problem that the information stored in the memory is reversed by radiation particles, thus reducing the reliability of the memory. The invention provides a storage unit resistant to single event reversal.

抗单粒子翻转的存储单元,它包括2个PMOS晶体管和8个NMOS晶体管,所述的2个PMOS晶体管分别为晶体管P1和P2,8个NMOS晶体管分别为晶体管N1至N8;A storage unit resistant to single event upset, which includes 2 PMOS transistors and 8 NMOS transistors, the 2 PMOS transistors are respectively transistors P1 and P2, and the 8 NMOS transistors are respectively transistors N1 to N8;

晶体管P2的源极、晶体管P1的源极、晶体管N5的漏极和晶体管N6的漏极均接供电电源,The source of the transistor P2, the source of the transistor P1, the drain of the transistor N5 and the drain of the transistor N6 are all connected to the power supply,

晶体管P2的漏极与晶体管P1的栅极、晶体管N6的栅极、晶体管N2的漏极同时连接,晶体管P2的漏极与晶体管P1的栅极的交点为节点C,The drain of the transistor P2 is connected to the gate of the transistor P1, the gate of the transistor N6, and the drain of the transistor N2 at the same time, and the intersection of the drain of the transistor P2 and the gate of the transistor P1 is a node C,

晶体管P2的栅极与晶体管P1的漏极、晶体管N4的漏极和晶体管N5的栅极同时连接,晶体管P1的漏极与晶体管N5的栅极的交点为节点D,The gate of the transistor P2 is connected to the drain of the transistor P1, the drain of the transistor N4 and the gate of the transistor N5 at the same time, and the intersection of the drain of the transistor P1 and the gate of the transistor N5 is a node D,

晶体管N6的源极与晶体管N8源极、晶体管N4的栅极、晶体管N3的漏极和晶体管N1的栅极同时连接,晶体管N4的栅极与晶体管N3的漏极的交点为存储单元输出节点A,The source of the transistor N6 is connected to the source of the transistor N8, the gate of the transistor N4, the drain of the transistor N3 and the gate of the transistor N1, and the intersection of the gate of the transistor N4 and the drain of the transistor N3 is the storage unit output node A ,

晶体管N4的源极与晶体管N3的源极、晶体管N1的源极和晶体管N2的源极同时接地,The source of the transistor N4 is grounded simultaneously with the source of the transistor N3, the source of the transistor N1 and the source of the transistor N2,

晶体管N5的源极与晶体管N7源极、晶体管N3的栅极、晶体管N1的漏极和晶体管N2的栅极同时连接,晶体管N2的栅极与晶体管N1的漏极的交点为存储单元输出节点B,The source of the transistor N5 is connected to the source of the transistor N7, the gate of the transistor N3, the drain of the transistor N1 and the gate of the transistor N2, and the intersection of the gate of the transistor N2 and the drain of the transistor N1 is the storage unit output node B ,

晶体管N7的栅极和晶体管N8的栅极均通过字线WL来接收控制开关操作的信号,Both the gates of the transistor N7 and the gates of the transistor N8 receive a signal for controlling the switching operation through the word line WL,

晶体管N7的漏极与位线BLN连接,晶体管N8的漏极与位线BL连接。The drain of transistor N7 is connected to bit line BLN, and the drain of transistor N8 is connected to bit line BL.

当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元处于存操作状态的具体过程为:当字线WL为低电平“0”的时候,晶体管N4、N6、N1和P2处于开态,剩下的晶体管都处于关态,该种情况下,完成存储单元的存操作。When the level of node A is "1", the level of node B is "0", the level of node C is "1", and the level of node D is "0", the storage unit is in the storage operation state The specific process is: when the word line WL is at a low level "0", the transistors N4, N6, N1 and P2 are in the on state, and the remaining transistors are in the off state. In this case, the storage of the memory cell is completed. operate.

当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元进行读操作的具体过程为:When the level of node A is "1", the level of node B is "0", the level of node C is "1", and the level of node D is "0", the storage unit performs a read operation The specific process is:

首先,位线BL和BLN被预充电到VDD,当字线WL为高电平“1”的时候,节点A保持高电平“1”状态,节点B保持低电平“0”状态,位线BLN通过晶体管N1和N7进行放电;First, the bit lines BL and BLN are precharged to VDD. When the word line WL is at a high level "1", node A maintains a high level "1" state, and node B maintains a low level "0" state. Line BLN is discharged through transistors N1 and N7;

然后,外围电路中的放大器将根据两条位线BL和BLN之间的电压差,将存储单元的状态输出,从而完成存储单元的读操作。Then, the amplifier in the peripheral circuit will output the state of the memory cell according to the voltage difference between the two bit lines BL and BLN, thereby completing the read operation of the memory cell.

当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元进行写操作的具体过程为:When the level of node A is "1", the level of node B is "0", the level of node C is "1", and the level of node D is "0", the storage unit performs a write operation The specific process is:

将位线BL下拉到低电平“0”,同时将位线BLN上拉到高电平“1”,当字线WL为高电平“1”时,晶体管N7和N8处于导通的状态,节点A被下拉到低电平“0”,节点B被上拉到高电平“1”,此时,晶体管P1、N2、N3和N5处于导通态,晶体管N4、N6、N1和P2,处于关闭状态,当字线WL回到低电平“0”时,所有节点均处于稳定状态,从而完成存储单元的写操作。Pull down the bit line BL to a low level "0", and pull up the bit line BLN to a high level "1". When the word line WL is at a high level "1", the transistors N7 and N8 are in a conducting state , node A is pulled down to low level "0", node B is pulled up to high level "1", at this time, transistors P1, N2, N3 and N5 are in the conduction state, transistors N4, N6, N1 and P2 , in an off state, when the word line WL returns to a low level "0", all nodes are in a stable state, thereby completing the write operation of the memory cell.

本发明带来的有益效果是,在本发明中,主要是采用了10个晶体管设计了一种抗单粒子翻转的存储单元来进行抗单粒子翻转的加固。本发明针对单粒子翻转效应,利用单粒子翻转的物理机制,设计了一种新型的抗单粒子翻转的存储单元,其具有面积小、功耗低以及对存储器性能影响较小的优点。由于该存储单元属于锁存器,因此本加固设计也是一个抗单粒子翻转的锁存器加固设计。The beneficial effect brought by the present invention is that, in the present invention, an anti-single event inversion storage unit is mainly designed by using 10 transistors to strengthen the anti-single event inversion. Aiming at the single event upset effect, the present invention utilizes the physical mechanism of the single event upset to design a novel anti-single event upset storage unit, which has the advantages of small area, low power consumption and less impact on memory performance. Since the storage unit belongs to a latch, this hardened design is also a latch hardened design against single event flipping.

附图说明Description of drawings

图1为本发明所述的抗单粒子翻转的存储单元。FIG. 1 is a memory cell resistant to single event turnover according to the present invention.

具体实施方式detailed description

具体实施方式一:参见图1说明本实施方式,本实施方式所述的抗单粒子翻转的存储单元,它包括2个PMOS晶体管和8个NMOS晶体管,所述的2个PMOS晶体管分别为晶体管P1和P2,8个NMOS晶体管分别为晶体管N1至N8;Specific Embodiment 1: Referring to FIG. 1 to illustrate this embodiment, the anti-single event reversal memory unit described in this embodiment includes 2 PMOS transistors and 8 NMOS transistors, and the 2 PMOS transistors are respectively transistor P1 and P2, the 8 NMOS transistors are respectively transistors N1 to N8;

晶体管P2的源极、晶体管P1的源极、晶体管N5的漏极和晶体管N6的漏极均接供电电源,The source of the transistor P2, the source of the transistor P1, the drain of the transistor N5 and the drain of the transistor N6 are all connected to the power supply,

晶体管P2的漏极与晶体管P1的栅极、晶体管N6的栅极、晶体管N2的漏极同时连接,晶体管P2的漏极与晶体管P1的栅极的交点为节点C,The drain of the transistor P2 is connected to the gate of the transistor P1, the gate of the transistor N6, and the drain of the transistor N2 at the same time, and the intersection of the drain of the transistor P2 and the gate of the transistor P1 is a node C,

晶体管P2的栅极与晶体管P1的漏极、晶体管N4的漏极和晶体管N5的栅极同时连接,晶体管P1的漏极与晶体管N5的栅极的交点为节点D,The gate of the transistor P2 is connected to the drain of the transistor P1, the drain of the transistor N4 and the gate of the transistor N5 at the same time, and the intersection of the drain of the transistor P1 and the gate of the transistor N5 is a node D,

晶体管N6的源极与晶体管N8源极、晶体管N4的栅极、晶体管N3的漏极和晶体管N1的栅极同时连接,晶体管N4的栅极与晶体管N3的漏极的交点为存储单元输出节点A,The source of the transistor N6 is connected to the source of the transistor N8, the gate of the transistor N4, the drain of the transistor N3 and the gate of the transistor N1, and the intersection of the gate of the transistor N4 and the drain of the transistor N3 is the storage unit output node A ,

晶体管N4的源极与晶体管N3的源极、晶体管N1的源极和晶体管N2的源极同时接地,The source of the transistor N4 is grounded simultaneously with the source of the transistor N3, the source of the transistor N1 and the source of the transistor N2,

晶体管N5的源极与晶体管N7源极、晶体管N3的栅极、晶体管N1的漏极和晶体管N2的栅极同时连接,晶体管N2的栅极与晶体管N1的漏极的交点为存储单元输出节点B,The source of the transistor N5 is connected to the source of the transistor N7, the gate of the transistor N3, the drain of the transistor N1 and the gate of the transistor N2, and the intersection of the gate of the transistor N2 and the drain of the transistor N1 is the storage unit output node B ,

晶体管N7的栅极和晶体管N8的栅极均通过字线WL来接收控制开关操作的信号,Both the gates of the transistor N7 and the gates of the transistor N8 receive a signal for controlling the switching operation through the word line WL,

晶体管N7的漏极与位线BLN连接,晶体管N8的漏极与位线BL连接。The drain of transistor N7 is connected to bit line BLN, and the drain of transistor N8 is connected to bit line BL.

本实施方式中,为了提高静态随机存取存储器在宇航和自然辐射环境下的可靠性能力,进行了对存储单元的抗单粒子翻转的加固设计。本发明可以对存储单元的单节点翻转和多节点翻转进行容错再恢复。本发明由10个MOS管来组成,分别是PMOS晶体管P1、P2以及NMOS晶体管N1、N2、N3、N4、N5、N6、N7和N8。本发明可以对存储单元中任意单个节点的翻转进行加固,还可以对固定的两个节点进行抗多节点翻转容错,而同时不依赖于所存储的值。In this implementation manner, in order to improve the reliability of the SRAM in spaceflight and natural radiation environments, a reinforced design for anti-single event upset of the storage unit is carried out. The invention can carry out fault-tolerant recovery for the single-node flip and multi-node flip of the storage unit. The present invention consists of 10 MOS transistors, which are respectively PMOS transistors P1 and P2 and NMOS transistors N1, N2, N3, N4, N5, N6, N7 and N8. The present invention can strengthen the flipping of any single node in the storage unit, and can also implement anti-multi-node flipping and fault tolerance for two fixed nodes without depending on the stored value at the same time.

具体实施方式二:参见图1说明本实施方式,本实施方式与具体实施方式一所述的抗单粒子翻转的存储单元的区别在于,当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元处于存操作状态的具体过程为:当字线WL为低电平“0”的时候,晶体管N4、N6、N1和P2处于开态,剩下的晶体管都处于关态,该种情况下,完成存储单元的存操作。Specific embodiment 2: Refer to FIG. 1 to illustrate this embodiment. The difference between this embodiment and the anti-single event upset memory cell described in Embodiment 1 is that when the level of node A is "1" and the voltage of node B is When level is "0", the level of node C is "1", and the level of node D is "0", the specific process that the memory cell is in the storage operation state is: when the word line WL is low level "0" ", the transistors N4, N6, N1 and P2 are in the on state, and the rest of the transistors are in the off state. In this case, the storage operation of the memory cell is completed.

具体实施方式三:参见图1说明本实施方式,本实施方式与具体实施方式一所述的抗单粒子翻转的存储单元的区别在于,当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元进行读操作的具体过程为:Specific embodiment 3: Refer to FIG. 1 to illustrate this embodiment. The difference between this embodiment and the anti-single event upset memory cell described in Embodiment 1 is that when the level of node A is "1" and the voltage of node B When the level is "0", the level of the node C is "1", and the level of the node D is "0", the specific process for the memory unit to perform the read operation is as follows:

首先,位线BL和BLN被预充电到VDD,当字线WL为高电平“1”的时候,节点A保持高电平“1”状态,节点B保持低电平“0”状态,位线BLN通过晶体管N1和N7进行放电;First, the bit lines BL and BLN are precharged to VDD. When the word line WL is at a high level "1", node A maintains a high level "1" state, and node B maintains a low level "0" state. Line BLN is discharged through transistors N1 and N7;

然后,外围电路中的放大器将根据两条位线BL和BLN之间的电压差,将存储单元的状态输出,从而完成存储单元的读操作。Then, the amplifier in the peripheral circuit will output the state of the memory cell according to the voltage difference between the two bit lines BL and BLN, thereby completing the read operation of the memory cell.

具体实施方式四:参见图1说明本实施方式,本实施方式与具体实施方式一所述的抗单粒子翻转的存储单元的区别在于,当节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”时,所述存储单元进行写操作的具体过程为:Embodiment 4: Refer to FIG. 1 to illustrate this embodiment. The difference between this embodiment and the anti-single event upset memory cell described in Embodiment 1 is that when the level of node A is "1" and the voltage of node B When the level is "0", the level of the node C is "1", and the level of the node D is "0", the specific process of the write operation of the storage unit is as follows:

将位线BL下拉到低电平“0”,同时将位线BLN上拉到高电平“1”,当字线WL为高电平“1”时,晶体管N7和N8处于导通的状态,节点A被下拉到低电平“0”,节点B被上拉到高电平“1”,此时,晶体管P1、N2、N3和N5处于导通态,晶体管N4、N6、N1和P2,处于关闭状态,当字线WL回到低电平“0”时,所有节点均处于稳定状态,从而完成存储单元的写操作。Pull down the bit line BL to a low level "0", and pull up the bit line BLN to a high level "1". When the word line WL is at a high level "1", the transistors N7 and N8 are in a conducting state , node A is pulled down to low level "0", node B is pulled up to high level "1", at this time, transistors P1, N2, N3 and N5 are in the conduction state, transistors N4, N6, N1 and P2 , in an off state, when the word line WL returns to a low level "0", all nodes are in a stable state, thereby completing the write operation of the memory cell.

本发明所述的抗单粒子翻转的存储单元的状态包括两种,一种为:节点A的电平为“1”、节点B的电平为“0”、节点C的电平为“1”、节点D的电平为“0”;另一种为:节点A的电平为“0”、节点B的电平为“1”、节点C的电平为“0”、节点D的电平为“1”。其中,节点A的电平为“0”、节点B的电平为“1”、节点C的电平为“0”、节点D的电平为“1”时的储单元进行存操作、读操作和写操作的具体过程,与节点A的电平为“0”、节点B的电平为“1”、节点C的电平为“0”、节点D的电平为“1”时的储单元进行存操作、读操作和写操作的过程相反。The state of the anti-single event flip memory unit of the present invention includes two states, one is: the level of node A is "1", the level of node B is "0", and the level of node C is "1". ", the level of node D is "0"; the other is: the level of node A is "0", the level of node B is "1", the level of node C is "0", the level of node D is The level is "1". Among them, when the level of node A is "0", the level of node B is "1", the level of node C is "0", and the level of node D is "1", the storage unit performs storage operation, read The specific process of operation and write operation is the same as when the level of node A is "0", the level of node B is "1", the level of node C is "0", and the level of node D is "1". The process of storage operation, read operation and write operation of the storage unit is reversed.

基于单粒子翻转产生的物理机制,当一个辐射粒子轰击PMOS晶体管的时候,只能产生正的瞬态电压脉冲;而轰击NMOS晶体管的时候,只能产生负的瞬态电压脉冲。因此,对于该状态而言,由于B节点没有与PMOS晶体管的栅极/漏极相连接,因此它不是敏感节点。考虑图1给定的状态A=1、B=0、C=1、D=0,敏感节点是节点A、C和D。在另一个存储状态,也就是A=0、B=1、C=0和D=1状态,敏感节点则是节点B、C和D。Based on the physical mechanism of single event inversion, when a radiation particle bombards a PMOS transistor, only a positive transient voltage pulse can be generated; when it bombards an NMOS transistor, only a negative transient voltage pulse can be generated. Therefore, node B is not a sensitive node for this state since it is not connected to the gate/drain of the PMOS transistor. Considering the given state A=1, B=0, C=1, D=0 in Fig. 1, the sensitive nodes are nodes A, C and D. In another storage state, that is, A=0, B=1, C=0 and D=1 states, sensitive nodes are nodes B, C and D.

在电荷共享引起的多节点翻转现象中,多余两个节点的电荷共享是不会引起存储器状态发生有效地改变,因此,本发明主要考虑对敏感节点A(B)、节点C和节点D进行抗单节点翻转加固以及两个敏感节点C和节点D进行抗多节点翻转加固。In the multi-node flipping phenomenon caused by charge sharing, the charge sharing of two redundant nodes will not cause effective changes in the state of the memory. Therefore, the present invention mainly considers the anti Single-node overturn reinforcement and two sensitive nodes C and D are anti-multi-node overturn reinforcement.

以A=1、B=0、C=1、D=0为例,本发明所述的抗单粒子翻转的存储单元的抗辐射性能分析如下:Taking A=1, B=0, C=1, and D=0 as examples, the anti-radiation performance analysis of the anti-single event flipping storage unit according to the present invention is as follows:

1、假设节点A被翻转到“0”状态,它将关断晶体管N1和N4,节点B、C和D将会保持各自原来状态,故剩余的晶体管仍然是保持原来的开或者关的状态,如晶体管N6将会保持开启状态。因此,节点A将会恢复到原来的“1”状态。1. Assuming that node A is flipped to "0" state, it will turn off transistors N1 and N4, and nodes B, C and D will maintain their original states, so the remaining transistors still maintain their original on or off states. For example, transistor N6 will remain on. Therefore, node A will revert to the original "1" state.

2、当节点C发生翻转到“0”的时候,晶体管P1和N6将会分别被打开和关闭。节点D将会被影响,它的值将是“1”,同时晶体管P2将会被暂时的关闭。但是,由于晶体管N4的宽长比大于晶体管P1的宽长比,因此,受影响的D节点将会很快被拉回到原来的低电平;因此,晶体管N5将会一直关闭,节点B并不会收到影响。同时,晶体管N4由于节点A没有改变而一直保持着开启状态,然后,晶体管P2将会恢复到开启状态,节点C被恢复到它原来的“1”状态。2. When the node C flips to "0", the transistors P1 and N6 will be turned on and off respectively. Node D will be affected, its value will be "1", and transistor P2 will be temporarily turned off. However, since the width-to-length ratio of transistor N4 is greater than that of transistor P1, the affected node D will quickly be pulled back to the original low level; therefore, transistor N5 will always be turned off, and node B will not will not be affected. At the same time, the transistor N4 remains on because the node A has not changed, and then the transistor P2 will turn back on, and the node C is restored to its original "1" state.

3、当节点D发生翻转的时候,晶体管P2被关闭,晶体管N5被暂时地开启。但是,由于晶体管N4的宽长比大于晶体管P1的宽长比,同时晶体管N4由于节点A没有改变而一直保持着开启状态,因此,受影响的D节点将会很快被拉回到原来的低电平。3. When the node D is flipped, the transistor P2 is turned off, and the transistor N5 is temporarily turned on. However, since the width-to-length ratio of transistor N4 is greater than that of transistor P1, and transistor N4 remains on since node A has not changed, the affected node D will quickly be pulled back to its original low level.

4、由于电荷共享效应的影响,节点C和D有可能被影响。此时,它的状态跟节点C被翻转一样,因此通过类似的分析,可以发现节点C和节点D都将会回复到原来的状态。4. Nodes C and D may be affected due to the charge sharing effect. At this time, its state is the same as that of node C being flipped, so through similar analysis, it can be found that both node C and node D will return to their original state.

对应的,如果设计的存储单元处于另外一个状态,也就是A=0、B=1、C=0和D=1状态,在节点C和D处发生的多节点发转也会被恢复。因此,节点C和D是两个固定的可从多节点翻转中恢复的节点,并且这两个节点与存储器存储的值无关。Correspondingly, if the designed storage unit is in another state, that is, A=0, B=1, C=0 and D=1, the multi-node forwarding at nodes C and D will also be restored. Therefore, nodes C and D are two fixed nodes recoverable from multi-node rollover, and these two nodes are independent of the value stored in the memory.

5、当节点A-C或者A-D发生多节点翻转的时候,晶体管N4将会被关闭,所以节点C或者D节点将不会恢复到原来的状态。此时,存储的状态发生了翻转。5. When node A-C or A-D has multi-node inversion, transistor N4 will be turned off, so node C or node D will not return to the original state. At this point, the stored state is flipped.

因此,为了最小化节点A-C(B-C)或A-D(B-D)发生多节点翻转的可能性,需要在版图设计中合理的考虑版图拓扑结构。因此,在版图绘制的时候,可以将节点A、节点B与节点C-D在版图的物理距离上绘制的比较远。Therefore, in order to minimize the possibility of node A-C (B-C) or A-D (B-D) multi-node flipping, it is necessary to reasonably consider the layout topology in the layout design. Therefore, when drawing the layout, nodes A, B, and C-D can be drawn relatively far apart in terms of the physical distance of the layout.

Claims (4)

1. primary particle inversion resistant memory cell, it is characterised in that it includes 2 PMOS transistors and 8 nmos pass transistors, institute The 2 PMOS transistors respectively transistor P1 and P2 for stating, 8 nmos pass transistors are respectively transistor N1 to N8;
The source electrode of transistor P2, the source electrode of transistor P1, the drain electrode of transistor N5 and the drain electrode of transistor N6 connect power supply,
The grid of the drain electrode of transistor P2 and transistor P1, the grid of transistor N6, the drain electrode of transistor N2 are connected simultaneously, crystal The drain electrode of pipe P2 is node C with the intersection point of the grid of transistor P1,
The grid of transistor P2 is connected simultaneously with the grid of the drain electrode, the drain electrode of transistor N4 and transistor N5 of transistor P1, brilliant The drain electrode of body pipe P1 is node D with the intersection point of the grid of transistor N5,
The source electrode of transistor N6 and the grid of transistor N8 source electrodes, the grid of transistor N4, the drain electrode of transistor N3 and transistor N1 Pole connects simultaneously, and the grid of transistor N4 is memory cell output node A with the intersection point of the drain electrode of transistor N3,
The source electrode of transistor N4 is grounded simultaneously with the source electrode of the source electrode, the source electrode of transistor N1 and transistor N2 of transistor N3,
The source electrode of transistor N5 and the grid of transistor N7 source electrodes, the grid of transistor N3, the drain electrode of transistor N1 and transistor N2 Pole connects simultaneously, and the grid of transistor N2 is memory cell output node B with the intersection point of the drain electrode of transistor N1,
The grid of transistor N7 and the grid of transistor N8 receive the signal of controlling switch operation by wordline WL,
The drain electrode of transistor N7 is connected with bit line BLN, and the drain electrode of transistor N8 is connected with bit line BL.
2. primary particle inversion resistant memory cell according to claim 1, it is characterised in that when the level of node A is When the level that the level of " 1 ", node B is " 0 ", the level of node C is " 1 ", node D is for " 0 ", the memory cell is in and deposits behaviour The detailed process for making state is:When wordline WL is low level " 0 ", transistor N4, N6, N1 and P2 are in ON state, are left Transistor all in OFF state, in the case of this kind, complete memory cell and deposit operation.
3. primary particle inversion resistant memory cell according to claim 1, it is characterised in that when the level of node A is When the level that the level of " 1 ", node B is " 0 ", the level of node C is " 1 ", node D is for " 0 ", the memory cell carries out reading behaviour The detailed process of work is:
First, bit line BL and BLN are precharged to VDD, and when wordline WL is high level " 1 ", node A keeps high level One state, node B keeps low level " 0 " state, and bit line BLN is discharged by transistor N1 and N7;
Then, the amplifier in peripheral circuit is by according to the voltage difference between two bit lines BL and BLN, by the state of memory cell Output, so as to complete the read operation of memory cell.
4. primary particle inversion resistant memory cell according to claim 1, it is characterised in that when the level of node A is When the level that the level of " 1 ", node B is " 0 ", the level of node C is " 1 ", node D is for " 0 ", the memory cell enters row write behaviour The detailed process of work is:
Bit line BL is pulled down into low level " 0 ", while bit line BLN is pulled upward to high level " 1 ", when wordline WL is high level " 1 " When, the state that transistor N7 and N8 are on, node A pulled down to low level " 0 ", and node B is essentially pulled up to high level " 1 ", Now, transistor P1, N2, N3 and N5 is on state, and transistor N4, N6, N1 and P2 are closed, when wordline WL is returned During to low level " 0 ", all nodes are in stable state, so as to complete the write operation of memory cell.
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