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CN103889069B - A kind of accidental access signal method of sending and receiving applied to large coverage - Google Patents

A kind of accidental access signal method of sending and receiving applied to large coverage Download PDF

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CN103889069B
CN103889069B CN201410119585.9A CN201410119585A CN103889069B CN 103889069 B CN103889069 B CN 103889069B CN 201410119585 A CN201410119585 A CN 201410119585A CN 103889069 B CN103889069 B CN 103889069B
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邓风
王俊
李洋
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Wuhan Research Institute of Posts and Telecommunications Co Ltd
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Abstract

本发明提供一种应用于大覆盖范围的随机接入信号发送和接收方法,步骤:用户设备配置RACH格式,RACH格式由CP长度设置包括M个重复24576Ts、TSEQ长度设置为N个重复24576Ts,M=1,N≥1;R为覆盖场景半径,C为光速,Ts=1/(15000*2048)s;由RACH占用长度调整其保护间隔GT至大于或等于往返路径时延;发送配置后的RACH信号,基站提取出N+2个24576Ts长的峰值检测序列;将N+2段峰值检测序列分别进行峰值检测;对每段并列检测的前导ID结果以及SINR的联合判决获得初始时偏值;通过判断同一个前导ID在N+1个并行检测窗中出现的情况,对初始时偏值进行校准获得正确的前导ID和时偏值;采用本发明可实现100KM以上的大范围覆盖,能够满足超远覆盖下的定时精度的要求,节约时频资源,对协议修改较小。

The present invention provides a method for sending and receiving random access signals applied to a large coverage area. The steps are: the user equipment configures the RACH format, the RACH format is set by the CP length to include M repetitions of 24576Ts, and the T SEQ length is set to N repetitions of 24576Ts, M=1, N≥1; R is the coverage scene radius, C is the speed of light, Ts=1/(15000*2048)s; the guard interval GT is adjusted by the RACH occupation length to be greater than or equal to the round-trip path delay; after sending the configured RACH signal, the base station extracts N +2 24576Ts long peak detection sequences; perform peak detection on N+2 peak detection sequences respectively; obtain the initial time offset value from the joint judgment of the leading ID results of each parallel detection and SINR; judge the same leading ID in In the case of N+1 parallel detection windows, the initial time offset value is calibrated to obtain the correct leading ID and time offset value; the invention can achieve a large-scale coverage of more than 100KM, and can meet the timing accuracy under ultra-long coverage Requirements, time-frequency resources are saved, and the modification of the protocol is minor.

Description

一种应用于大覆盖范围的随机接入信号发送和接收方法A random access signal transmission and reception method applied to a large coverage area

技术领域technical field

本发明涉及移动通信系统频分双工长期演进(FDD-LTE)领域,尤其涉及一种大覆盖下的随机接入信号发送和接收方法,本发明属于通信领域。The invention relates to the field of frequency division duplex long-term evolution (FDD-LTE) of mobile communication systems, in particular to a method for sending and receiving random access signals under large coverage, and the invention belongs to the field of communication.

背景技术Background technique

LTE-FDD系统中,用户设备通过随机接入过程与基站建立上行初始同步,用户设备的初始定时提前量(TA)通过随机接入信道测量上报,因此,能否正确估计出TA,对用户设备能否获得上行传输时间同步,以及后面能否被正确调度进行上行传输有着重要的影响。In the LTE-FDD system, the user equipment establishes uplink initial synchronization with the base station through the random access process, and the initial timing advance (TA) of the user equipment is reported through random access channel measurement. Whether the uplink transmission time synchronization can be obtained, and whether it can be correctly scheduled for uplink transmission later has an important impact.

目前LTE-FDD系统随机接入信道(RACH)的前导格式有4种,每种格式都有各自的循环前缀(CP)以及序列(TSEQ)长度,并且不同的CP和TSEQ长度都有其对应的可达的小区半径及时延范围。已设计的这些前导格式中,前导格式3的CP长为21024Ts,TSEQ是由两个24576Ts长的重复序列组成,采用传统前导检测方法,该格式能支持的最大时延为24576Ts,对应100KM左右的覆盖半径,不适合在不增加基站设备的前提下用于半径超过100KM的特殊场景,在100KM的以上的特殊场景下,使用现有的前导格式和其传统检测算法,会导致TA估计错误,将影响用户设备取得上行同步的成功率。At present, there are four types of preamble formats for Random Access Channel (RACH) in LTE-FDD system, each format has its own cyclic prefix (CP) and sequence (T SEQ ) length, and different CP and T SEQ lengths have their own The corresponding reachable cell radius and delay range. Among the preamble formats that have been designed, the CP length of the preamble format 3 is 21024Ts, and the T SEQ is composed of two 24576Ts long repetitive sequences. Using the traditional preamble detection method, the maximum delay that this format can support is 24576Ts, corresponding to about 100KM The coverage radius is not suitable for special scenarios with a radius of more than 100KM without adding base station equipment. In special scenarios with a radius of more than 100KM, using the existing preamble format and its traditional detection algorithm will lead to TA estimation errors. It will affect the success rate of the user equipment to obtain uplink synchronization.

为了覆盖更大的范围,传统发送方法需要通过覆盖需求配置RACH相应的CP和保护间隔(GT)长度来抵消往返时延,即小区覆盖范围越大,传输时延越长,需要的CP和GT越大,同时还需增加RACH的TSEQ长度及频域带宽,使得RACH满足系统的定时精度需求,造成时频资源的浪费。In order to cover a larger area, the traditional transmission method needs to configure the corresponding CP and guard interval (GT) length of RACH according to the coverage requirements to offset the round-trip delay, that is, the larger the cell coverage, the longer the transmission delay, and the required CP and GT The larger the T SEQ length and the frequency domain bandwidth of the RACH need to be increased at the same time, so that the RACH can meet the timing accuracy requirements of the system, resulting in a waste of time-frequency resources.

发明内容Contents of the invention

本发明的目的是提供一种提高覆盖能力的随机信号接入发送和接收方法,以便在扩大覆盖范围的同时,节约系统时频资源。The purpose of the present invention is to provide a random signal access sending and receiving method with improved coverage, so as to save system time-frequency resources while expanding the coverage.

本发明所采用的技术方案是:The technical scheme adopted in the present invention is:

一种应用于大覆盖范围的随机接入信号发送和接收方法,包括如下步骤:用户设备配置随机接入信道RACH格式,RACH格式的CP长度设置包括M个重复的24576Ts、TSEQ长度设置为N个重复的24576Ts,其中M=1,N≥1;N由公式R为覆盖场景半径,C为光速,Ts=1/(15000*2048) s获得;由RACH信号占用长度调整RACH信号的保护间隔GT至大于或等于往返路径时延;用户设置发送配置后的RACH信号至基站,基站提取出N+2个24576Ts长的峰值检测序列;将N+2段峰值检测序列分别进行峰值检测;对每段并列检测的前导ID结果以及SINR的联合判决获得初始时偏值;通过判断同一个前导ID在N+1个并行检测窗中出现的情况,对初始时偏值进行校准获得正确的前导ID和时偏值,随机接入信号接收成功。A method for sending and receiving random access signals applied to a large coverage area, comprising the following steps: user equipment configures a random access channel RACH format, the CP length setting of the RACH format includes M repeated 24576Ts, and the T SEQ length is set to N Repeated 24576Ts, where M=1, N≥1; N is determined by the formula R is the radius of the coverage scene, C is the speed of light, obtained by Ts= 1/(15000*2048) s ; the guard interval GT of the RACH signal is adjusted by the RACH signal occupation length to be greater than or equal to the round-trip path delay; the user sets and sends the configured RACH The signal is sent to the base station, and the base station extracts N+2 24576Ts long peak detection sequences; performs peak detection on the N+2 peak detection sequences respectively; obtains the initial time offset value for the joint judgment of the leading ID result of each parallel detection and the SINR ; By judging the appearance of the same preamble ID in N+1 parallel detection windows, the initial time offset value is calibrated to obtain the correct preamble ID and time offset value, and the random access signal is received successfully.

所述峰值检测序列提取过程为:将提取出的序列以24576Ts长从头往后依此划分为第1段,第2段...第N+2段的段序列,对段序列分别进行并行峰值检测,记录每段峰值检测的前导序列ID和时间偏移量结果以及第N+1段和第N+2段检测窗中的SINR。The extraction process of the peak detection sequence is as follows: the extracted sequence is divided into the first segment, the second segment...the segment sequence of the N+2 segment with a length of 24576Ts from the beginning to the end, and the parallel peak value is performed on the segment sequence respectively. Detection, record the leading sequence ID and time offset results of each peak detection and the SINR in the detection window of the N+1 and N+2 segments.

所述初始时偏值获得过程如下:除去段序列中的第N+2段的检测结果,当第N+1段以及剩余N段中的至少一段检测到相同前导ID,则将第N+1段序列估计的时偏值作为初始时偏值;除去段序列中的第N+2段的检测结果,当同一个前导ID只在第N+1段出现,则比较N+1段和N+2段的SINR,取SINR大的那段序列估计出来的时偏值作为初始时偏值。The process of obtaining the initial time offset value is as follows: remove the detection result of the N+2th segment in the segment sequence, and when the same leading ID is detected in the N+1th segment and at least one of the remaining N segments, then the N+1th segment The time offset value estimated by the segment sequence is used as the initial time offset value; the detection result of the N+2 segment in the segment sequence is removed, and when the same leading ID only appears in the N+1 segment, compare the N+1 segment with the N+ For the SINR of 2 segments, the time offset value estimated from the sequence with the larger SINR is taken as the initial time offset value.

所述N+2段峰值检测序列分别进行峰值检测方法为:将每段峰值检测序列频移到DC处,对序列进行滤波和下采样,得到长度为2048Ts的序列,进行2048点快速傅里叶变换,从中提取出839点原ZC序列,用ZC序列本地母码的频域序列与接收的RACH频域序列的复共轭相乘,进行1536点的离散傅里叶逆变换,得到PDP时域相关值;将PDP时延相关值取均值,根据PDP均值进行门限值的设定和峰值的检测,记录每段检测到的前导序列ID以及对应的时偏值,计算获得SINR。The peak detection method of the N+2 sections of peak detection sequences is as follows: each section of the peak detection sequence is frequency-shifted to DC, the sequence is filtered and down-sampled to obtain a sequence with a length of 2048Ts, and a 2048-point fast Fourier transform is performed Transform, extract 839 points of the original ZC sequence from it, multiply the frequency domain sequence of the ZC sequence local mother code with the complex conjugate of the received RACH frequency domain sequence, and perform a discrete Fourier inverse transform of 1536 points to obtain the PDP time domain Correlation value: take the average value of the PDP time delay correlation value, set the threshold value and detect the peak value according to the PDP average value, record the detected preamble sequence ID and the corresponding time offset value of each segment, and calculate the SINR.

所述时偏校准包括三种方式:I)除去第N+2段的检测结果,当同一个前导ID在前N+1个并行峰值检测中都出现时,初始时偏值不需校准,将初始时偏值作为最后上报的时偏值;II)除去第N+2段的检测结果,当同一个前导ID在第1...M(M=1...N)个峰值检测中未出现,而在剩下的N+1-M个峰值检测中出现时,将初始时偏值加上M*24576Ts得到校准值,将校准值作为最后上报的时偏值;III)除去第N+2段的检测结果,当同一个前导ID在N+1个峰值检测中都未出现时,时延过大导致随机接入失败或者未发该前导ID。所述SINR值为检测窗中的PDP峰值能量与总的PDP能量比值。所述PDP峰值能量为PDP峰值最大值能量加上峰值附近点的能量。The time offset calibration includes three methods: 1) remove the detection result of the N+2 section, when the same preamble ID appears in the first N+1 parallel peak detections, the initial time offset value does not need to be calibrated, and the The initial time offset value is used as the last reported time offset value; II) The detection result of the N+2 segment is removed, when the same preamble ID is not detected in the 1...M (M=1...N) peak detection appears, and when it appears in the remaining N+1-M peak detections, add the initial time offset value to M*24576Ts to obtain the calibration value, and use the calibration value as the last reported time offset value; III) remove the N+th For the detection results of stage 2, when the same preamble ID does not appear in the N+1 peak detections, the time delay is too large and random access fails or the preamble ID is not sent. The SINR value is a ratio of the PDP peak energy in the detection window to the total PDP energy. The PDP peak energy is the PDP peak maximum energy plus the energy of points near the peak.

本发明具有如下优点:The present invention has the following advantages:

为了在100KM以上的大覆盖场景下成功接入,本发明提供一种适用于100KM以上的大覆盖随机接入方法,该方法不改变RACH占用的频域资源,所需增加的额外时域资源较小,同时能保证系统性能,节约系统资源、减少开销。In order to successfully access in a large coverage scenario above 100KM, the present invention provides a random access method suitable for large coverage above 100KM. This method does not change the frequency domain resources occupied by RACH, and the additional time domain resources required are relatively Small, while ensuring system performance, saving system resources, and reducing overhead.

附图说明Description of drawings

图1为本发明设计的RACH前导结构示意图;Fig. 1 is the RACH preamble structure schematic diagram that the present invention designs;

图2为本发明RACH峰值检测序列提取示意图;Fig. 2 is a schematic diagram of extracting the RACH peak detection sequence of the present invention;

图3为本发明RACH发送方法的实现流程图;Fig. 3 is the implementation flowchart of the RACH transmission method of the present invention;

图4为本发明的基站侧RACH检测流程图;Fig. 4 is the RACH detection flowchart of the base station side of the present invention;

图5为本发明基站侧RACH检测部分流程图;FIG. 5 is a flow chart of the RACH detection part at the base station side of the present invention;

图6为本发明实施例1中RACH前导的结构示意图;FIG. 6 is a schematic structural diagram of the RACH preamble in Embodiment 1 of the present invention;

图7为本发明实施例1中RACH峰值检测序列提取示意图;7 is a schematic diagram of extraction of RACH peak detection sequence in Embodiment 1 of the present invention;

图8为本发明实施例2中RACH前导的结构示意图;FIG. 8 is a schematic structural diagram of the RACH preamble in Embodiment 2 of the present invention;

图9为本发明实施例2中RACH峰值检测序列提取示意图;FIG. 9 is a schematic diagram of extraction of RACH peak detection sequence in Embodiment 2 of the present invention;

具体实施方式detailed description

下面结合各个实施例,对本发明的主要实现原理、具体实施方式及其能够达到的有益效果进行详细阐述。The main realization principles, specific implementation methods and beneficial effects that can be achieved of the present invention will be described in detail below in combination with various embodiments.

本发明所涉及一种应用于大覆盖范围的随机接入信号发送和接收方法,包括如下步骤:用户设备配置随机接入信道RACH格式,如图1所示,RACH格式的CP长度设置包括M个重复的24576Ts、TSEQ长度设置为N个重复的24576Ts,其中M=1,N≥1;N由公式R为覆盖场景半径,C为光速,Ts=1/(15000*2048)s获得;由RACH信号占用长度调整RACH信号的保护间隔GT至大于或等于往返路径时延;用户设置发送配置后的RACH信号至基站,基站提取出N+2个24576Ts长的峰值检测序列;将N+2段峰值检测序列分别进行峰值检测;对每段并列检测的前导ID结果以及SINR的联合判决获得初始时偏值;通过判断同一个前导ID在N+1个并行检测窗中出现的情况,对初始时偏值进行校准获得正确的前导ID和时偏值,随机接入信号接收成功。The present invention relates to a random access signal sending and receiving method applicable to a large coverage area, including the following steps: the user equipment configures the random access channel RACH format, as shown in Figure 1, the CP length setting of the RACH format includes M Repeated 24576Ts, T SEQ length is set to N repeated 24576Ts, where M=1, N≥1; N is determined by the formula R is the coverage scene radius, C is the speed of light, obtained by Ts= 1 /( 15000*2048 ) s ; the guard interval GT of the RACH signal is adjusted by the RACH signal occupation length to be greater than or equal to the round-trip path delay; the user sets and sends the configured RACH The signal is sent to the base station, and the base station extracts N+2 24576Ts long peak detection sequences; performs peak detection on the N+2 peak detection sequences respectively; obtains the initial time offset value for the joint judgment of the leading ID result of each parallel detection and the SINR ; By judging the appearance of the same preamble ID in N+1 parallel detection windows, the initial time offset value is calibrated to obtain the correct preamble ID and time offset value, and the random access signal is received successfully.

本发明实施例分别针对100KM以上和100KM以内覆盖进行详细说明,实施例1和实施例2是100KM以上覆盖范围的举例,分别针对200KM和360KM覆盖情况,实施例3是100KM覆盖举例。The embodiments of the present invention are respectively described in detail for the coverage above 100KM and within 100KM. Embodiment 1 and Embodiment 2 are examples of coverage above 100KM, respectively, for coverage of 200KM and 360KM. Embodiment 3 is an example of coverage of 100KM.

本发明实施例1:Embodiment 1 of the present invention:

在不改变LTERACH频域资源的情况下,以覆盖200KM小区为实施例,对本发明的发送方法和接收方法进行阐述。Under the condition of not changing the LTERACH frequency domain resource, the sending method and the receiving method of the present invention are described by taking the coverage of 200KM cells as an example.

本实施例共3个用户,低速场景下,发送的随机接入前导ID号分别为0,1,2,Ncs=0,实施例中每个用户的路径时延分别为1000Ts(100KM以内),35000Ts(100~200KM以内),50000Ts(超过200KM)。In this embodiment, there are 3 users. In the low-speed scenario, the sent random access preamble ID numbers are 0, 1, 2, and Ncs=0. The path delay of each user in the embodiment is 1000Ts (within 100KM). 35000Ts (within 100~200KM), 50000Ts (over 200KM).

下面结合附图2和图3对本发明实施例1发送方法进行详细说明,发送方法包括以下步骤:The sending method of embodiment 1 of the present invention will be described in detail below in conjunction with accompanying drawings 2 and 3, and the sending method includes the following steps:

步骤201,用户设备按照如下方法配置RACH;Step 201, the user equipment configures RACH according to the following method;

在不改变频域资源的情况下,此时要覆盖200KM的小区,本发明的发送方法为:首先计算N的大小,此时R=200KM,根据N的计算公式 得到N=1,TSEQ长度为24576Ts,CP长度为24576Ts,往返路径时延达到1.34ms,保护间隔GT长度取1.34ms,则RACH下总长度为2*24576Ts+1.34ms=1.6ms+1.34ms=2.94ms,总共只需要3个TTI,由于总共占用3个TTI,因此将GT长度调整为1.4ms。GT按照传统方法设计,即计算出往返时延后,GT可以根据RACH信号占用的长度适当调大,保护间隔GT大于等于最大往返时延。In the case of not changing the frequency domain resources, at this time, a cell of 200KM is to be covered. The transmission method of the present invention is: first calculate the size of N, at this time R=200KM, according to the calculation formula of N Get N=1, T SEQ length is 24576Ts, CP length is 24576Ts, round-trip path delay reaches 1.34ms, guard interval GT length is 1.34ms, then the total length under RACH is 2*24576Ts+1.34ms=1.6ms+1.34ms =2.94ms, only 3 TTIs are needed in total, since 3 TTIs are occupied in total, the GT length is adjusted to 1.4ms. The GT is designed according to the traditional method, that is, after the round-trip delay is calculated, the GT can be appropriately adjusted according to the length occupied by the RACH signal, and the guard interval GT is greater than or equal to the maximum round-trip delay.

本发明实施例中200KM覆盖的RACH前导结构示意图如图6所示,采用本发明的发送和接收方法,所需要的时频资源开销和LTE现有前导格式3相同,前导格式3是协议里面规定的覆盖范围最大的一种RACH格式,其覆盖范围为100KM,而本发明的发送和接收方法可以覆盖200KM,有效的节约了时频资源,扩大了系统的覆盖范围;同时,本前导格式只是在时域上更改RACH信号,频域保持不变,对协议改动较小,更改起来方便,易于实现。The schematic diagram of the RACH preamble structure covered by 200KM in the embodiment of the present invention is shown in Figure 6. Using the sending and receiving method of the present invention, the required time-frequency resource overhead is the same as that of LTE's existing preamble format 3, which is specified in the protocol A RACH format with the largest coverage, its coverage is 100KM, and the sending and receiving method of the present invention can cover 200KM, effectively saves time-frequency resources, and expands the coverage of the system; at the same time, this preamble format is only in The RACH signal is changed in the time domain, while the frequency domain remains unchanged, and the protocol is changed slightly, which is convenient and easy to implement.

特别的,本实施例中的前导格式如果只需覆盖100KM范围,可以不使用本发明的接收方法,采用传统的接收方法即可,和现有前导格式3需要的时频资源开销以及可覆盖的范围相同。In particular, if the preamble format in this embodiment only needs to cover a range of 100KM, the receiving method of the present invention may not be used, and the traditional receiving method may be used, and the time-frequency resource overhead required by the existing preamble format 3 and the coverage Same range.

步骤202,得到新RACH前导,并按照RACH配置方式发送RACH信号。In step 202, a new RACH preamble is obtained, and an RACH signal is sent according to the RACH configuration mode.

下面结合附图4对本发明实施例1提高覆盖能力的接收方法进行详细说明,随机接入信号接收方法包括以下步骤:The receiving method of embodiment 1 of the present invention to improve the coverage capability will be described in detail below in conjunction with accompanying drawing 4. The method for receiving random access signals includes the following steps:

步骤401,峰值检测序列提取:基站侧接收随机接入信号,根据前导配置索引获得前导的时域位置,提取出包括CP和序列以及部分GT在内的共(N+2)*24576Ts长的数据,由于本实施例中N=1,则提取出3个24576Ts长的序列,将数据从前往后依此划分为3段,如图7所示;Step 401, peak detection sequence extraction: the base station side receives the random access signal, obtains the time domain position of the preamble according to the preamble configuration index, and extracts (N+2)*24576Ts long data including CP, sequence and part of GT , since N=1 in this embodiment, then extract 3 long sequences of 24576Ts, and divide the data into 3 sections from front to back, as shown in Figure 7;

步骤402,进行峰值并行检测:将3个峰值检测序列分别进行并行峰值检测。记录下每段检测到的前导序列ID、时偏量以及功率延迟谱(PDP)的信噪比(SINR)。Step 402, performing parallel peak detection: performing parallel peak detection on the three peak detection sequences respectively. Record the preamble ID, time offset, and power delay profile (PDP) signal-to-noise ratio (SINR) for each detected segment.

本实施例结合图5对步骤402进行详细说明:This embodiment describes step 402 in detail in conjunction with FIG. 5:

步骤501,对每个序列进行峰值检测时,将每段峰值检测序列频移到直流(DC)处,对序列进行滤波和12倍的下采样,得到长度为2048Ts的序列,进行2048点快速傅里叶变换(FFT),从中提取出839点原Zadoff-Chu(ZC)序列,用ZC序列本地母码的频域序列与接收的RACH频域序列的复共轭相乘,进行1536点的离散傅里叶逆变换(IDFT),得到PDP时域相关值。Step 501, when performing peak detection on each sequence, shift the frequency of each peak detection sequence to direct current (DC), filter the sequence and down-sample by 12 times, obtain a sequence with a length of 2048Ts, and perform 2048-point fast Fu Liye transform (FFT), from which 839 points of the original Zadoff-Chu (ZC) sequence are extracted, and the frequency domain sequence of the local mother code of the ZC sequence is multiplied by the complex conjugate of the received RACH frequency domain sequence, and 1536 points are discrete Inverse Fourier transform (IDFT) to obtain the time-domain correlation value of the PDP.

步骤502,将PDP取平均值,根据PDP均值进行门限值的设定和峰值的检测,遍历64个根序列,检测用户的前导ID和时间偏移量,计算获得检测窗的N+1和N+2段的SINR值。根据自相关法估计时偏方法比较成熟,此处不做过多阐述。本步骤中计算获得峰值检测的SINR为检测窗中的PDP峰值能量与总的PDP能量比值。PDP峰值能量为PDP峰值最大值能量加上峰值附近的若干点的能量,本发明中可以选择峰值附近的6个点的能量,因为839点ZC序列经过K点(例如K=1536)IDFT计算PDP时冲击展宽导致能量散落。Step 502, average the PDP, set the threshold value and detect the peak value according to the PDP average value, traverse 64 root sequences, detect the preamble ID and time offset of the user, and calculate and obtain the N+1 and SINR value of segment N+2. The method of estimating time bias based on the autocorrelation method is relatively mature, and will not be elaborated here. In this step, the calculated SINR for peak detection is the ratio of the PDP peak energy in the detection window to the total PDP energy. The PDP peak energy is the PDP peak maximum energy plus the energy of several points near the peak. In the present invention, the energy of 6 points near the peak can be selected, because the 839-point ZC sequence passes K points (for example, K=1536) IDFT to calculate PDP When the impact broadens, the energy is scattered.

步骤403,获取初始时偏:通过对每段并行检测的前导ID结果以及SINR的联合判决获得初始时偏值。先不考虑第3段的检测结果:如果同一个前导ID不只是在第2段检测到,即在第1和第2段都检测到,则将第2段估计的时偏值作为初始时偏值;如果同一个前导ID只在第2段出现,则比较2段和3段的SINR,取SINR大的那段序列估计出来的时偏值作为初始时偏值;如果同一个前导ID在第1段和第2段都没有出现,认为没有该用户。Step 403, obtain initial time offset: obtain the initial time offset value through the joint judgment of the preamble ID result and SINR of each segment of parallel detection. Regardless of the detection result of the third paragraph: if the same preamble ID is not only detected in the second paragraph, that is, it is detected in both the first and second paragraphs, then the time offset value estimated in the second paragraph is used as the initial time offset value; if the same preamble ID only appears in the second segment, compare the SINR of the second segment and the third segment, and take the estimated time offset value of the sequence with a larger SINR as the initial time offset value; if the same preamble ID appears in the second segment Neither paragraph 1 nor paragraph 2 appears, and it is considered that there is no such user.

本实施例共3个用户路径时延分别为1000Ts(100KM以内),35000Ts(100~200KM以内),50000Ts(超过200KM)。如图6所示,用户1(时延为1000Ts)落在[0~24576)Ts内,在第1和第2段都检测到,将第2段估计的时偏值作为初始时偏值,时偏值为1000Ts;用户2(时延为35000Ts)落在[24576Ts~2*24576)Ts内,只在第2段都检测到,比较2段和3段的SINR,第3段的SINR大,取第3段估计出来的时偏值作为初始时偏值,时偏值为10424Ts;用户3(时延为60000Ts)超过2*24576Ts,在第1段和第2段峰值检测中都未出现前导ID2,用户3时偏过大超过该前导格式时偏范围,用户3随机接入失败。In this embodiment, the delays of three user paths are 1000Ts (within 100KM), 35000Ts (within 100-200KM), and 50000Ts (over 200KM). As shown in Figure 6, user 1 (with a delay of 1000Ts) falls within [0-24576) Ts and is detected in both the first and second sections, and the estimated time offset value in the second section is used as the initial time offset value. The time offset value is 1000Ts; user 2 (with a delay of 35000Ts) falls within [24576Ts~2*24576) Ts, and is only detected in the second segment. Comparing the SINR of the second segment and the third segment, the SINR of the third segment is larger , take the time offset value estimated in the third section as the initial time offset value, and the time offset value is 10424Ts; user 3 (with a delay of 60000Ts) exceeds 2*24576Ts, which does not appear in the peak detection of the first and second sections The preamble ID2 and the time offset of user 3 are too large and exceed the range of the preamble format time offset, and the random access of user 3 fails.

步骤404,进行校准:通过判断同一个用户的前导ID在N+1个并行检测窗中出现的情况,分别进行不同的时偏校准,得到正确的时偏。此处前导为一个用户的前导ID,不同用户的前导ID是不相同,此步骤是同一个用户在N+1段被检测出来的情况。Step 404, perform calibration: by judging the occurrence of the leading ID of the same user in N+1 parallel detection windows, different time offset calibrations are performed respectively to obtain the correct time offset. The leading ID here is the leading ID of a user, and the leading IDs of different users are different. This step is the case where the same user is detected in the N+1 segment.

在本实施例中,先不看第3段的检测结果,用户1的前导ID在第1段和第2段2个并行峰值检测中都出现时,初始时偏值不需校准,初始时偏值作为最后上报的时偏值,即1000TS作为最后时偏值;用户2的前导ID在第1个峰值检测中未出现而在第2个峰值检测中出现时,即在第1段未出现而在第2段出现时,将初始时偏值加上24576Ts得到校准值35000Ts,将校准值作为最后上报的时偏值;用户3的前导ID在3个峰值检测中都未出现时,时延过大导致随机接入失败。因此,在N=1情况下,使用该系统能检测的最大时偏范围为(1+1)*24576Ts=49152Ts。In this embodiment, regardless of the detection results in the third section, when the leading ID of user 1 appears in the two parallel peak detections in the first section and the second section, the initial time offset value does not need to be calibrated, and the initial time offset value as the last reported time offset value, that is, 1000TS as the last time offset value; when the leading ID of user 2 does not appear in the first peak detection but appears in the second peak detection, that is, it does not appear in the first segment but When the second paragraph appears, add 24576Ts to the initial time offset value to obtain a calibration value of 35000Ts, and use the calibration value as the last reported time offset value; when the leading ID of user 3 does not appear in the three peak detections, the delay exceeds A large value causes random access to fail. Therefore, in the case of N=1, the maximum time offset range that can be detected by this system is (1+1)*24576Ts=49152Ts.

例如,在不改变频域资源的情况下覆盖200KM的小区,此时往返路径时延达到1.34ms,采用传统设计方式和检测算法,不考虑最大时延扩展,CP和GT部分至少需要2.68ms,同时TSEQ需要将839RACH序列改变采样进行拉长到至少1.34ms,总共需要4.02ms,需要占用5个TTI。而采用本发明的发送方法和检测方法,取N=1,可检测2*24576Ts=1.6ms的时延,GT长度取1.34ms,总长度1.6+1.34=2.94ms,使用3个TTI足够覆盖200KM。For example, to cover a 200KM cell without changing the frequency domain resources, the round-trip path delay reaches 1.34ms at this time. Using the traditional design method and detection algorithm, regardless of the maximum delay extension, the CP and GT parts need at least 2.68ms. At the same time, T SEQ needs to lengthen the 839RACH sequence change sampling to at least 1.34ms, which takes 4.02ms in total and takes up 5 TTIs. However, with the transmission method and detection method of the present invention, if N=1, the time delay of 2*24576Ts=1.6ms can be detected, the GT length is 1.34ms, the total length is 1.6+1.34=2.94ms, and 3 TTIs are enough to cover 200KM .

本发明实施例2:Embodiment 2 of the present invention:

在不改变LTERACH频域资源的情况下,以覆盖360KM小区为实施例,对本发明的发送方法和接收方法进行阐述。本实施例共4个用户,低速场景下,发送的随机接入前导ID号分别为0,1,2,3,Ncs=0,仿真中加的路径时延分别为1000Ts(100KM以内),35000Ts(100~200KM以内),70000Ts(200KM~360KM)、80000Ts(超过360KM)。Under the condition of not changing the LTERACH frequency domain resource, the sending method and the receiving method of the present invention are described by taking the coverage of 360KM cells as an example. In this embodiment, there are 4 users in total. In the low-speed scenario, the sent random access preamble ID numbers are 0, 1, 2, 3, Ncs=0, and the path delay added in the simulation is 1000Ts (within 100KM), 35000Ts (within 100-200KM), 70000Ts (200KM-360KM), 80000Ts (over 360KM).

本发明实施例2发送方法包括以下步骤:The sending method in Embodiment 2 of the present invention includes the following steps:

步骤201,按照如下方法配置RACH;Step 201, configure RACH according to the following method;

在不改变频域资源的情况下,此时要覆盖360KM的小区,本发明的发送方法为:首先计算N的大小,此时R=360Km,根据N的计算公式 得到N=2,序列长度为2*24576Ts,CP长度为24576Ts,往返路径时延达到2.412ms,GT长度取2.412ms,则RACH总长度为3*24576Ts+2.412ms=2.4ms+2.412ms=4.812ms,总共只需要5个TTI,由于总共占用5个TTI,因此将GT长度调整为2.6ms。本发明实施例中360KM覆盖的RACH前导结构示意图如图8所示。In the case of not changing the frequency domain resources, at this time, a cell of 360KM is to be covered. The transmission method of the present invention is: first calculate the size of N, at this time R=360Km, according to the calculation formula of N Get N=2, the sequence length is 2*24576Ts, the CP length is 24576Ts, the round-trip path delay reaches 2.412ms, and the GT length is 2.412ms, then the total length of RACH is 3*24576Ts+2.412ms=2.4ms+2.412ms=4.812 ms, only 5 TTIs are required in total, and since 5 TTIs are occupied in total, the GT length is adjusted to 2.6ms. A schematic diagram of the RACH preamble structure covered by 360KM in the embodiment of the present invention is shown in FIG. 8 .

在不改变频域资源的情况下覆盖360KM的小区,当采用传统设计方式和检测算法,CP和GT部分至少需要4.824ms,同时序列部分需要将839RACH序列改变采样进行拉长到至少2.4ms,总共需要7.224ms,需要占用8个TTI。而采用本发明的发送方法和检测方法,仅需用5个TTI,有效的节约了系统时域资源。To cover a 360KM cell without changing the frequency domain resources, when the traditional design method and detection algorithm are used, the CP and GT parts need at least 4.824ms, and the sequence part needs to stretch the 839RACH sequence change sampling to at least 2.4ms. It takes 7.224ms and takes up 8 TTIs. However, by adopting the sending method and detection method of the present invention, only 5 TTIs are needed, which effectively saves system time domain resources.

步骤202,得到新RACH前导,并按照RACH配置方式发送新前导。Step 202, obtain a new RACH preamble, and send the new RACH preamble according to the RACH configuration mode.

本发明提高覆盖能力的接收装置包括以下步骤:The receiving device for improving coverage capability of the present invention includes the following steps:

步骤401,峰值检测序列提取:基站侧接收随机接入信号,根据前导配置索引获得前导的时域位置,提取出包括CP和序列以及部分GT在内的共(N+2)*24576Ts长的数据,由于本实施例2中N=2,则提取出4个24576Ts长的序列,将数据从前往后依此划分为4段;Step 401, peak detection sequence extraction: the base station side receives the random access signal, obtains the time domain position of the preamble according to the preamble configuration index, and extracts (N+2)*24576Ts long data including CP, sequence and part of GT , since N=2 in the present embodiment 2, then extract 4 sequences with a length of 24576Ts, and divide the data into 4 sections from front to back;

步骤402,进行峰值并行检测:将4个峰值检测序列分别进行并行峰值检测。记录下每段检测到的前导序列ID、时间偏移量以及计算检测窗中的SINR。Step 402, performing parallel peak detection: performing parallel peak detection on the four peak detection sequences respectively. Record each detected preamble ID, time offset and calculate the SINR in the detection window.

实施例1对步骤402进行了详细描述,此处不赘述。Embodiment 1 has described step 402 in detail, and details are not repeated here.

步骤403,获取初始时偏:通过对每段并行检测的前导ID结果以及SINR的联合判决获得初始时偏值。先不考虑第4段的检测结果:如果同一个前导ID不只是第3段检测到,即在第3段以及至少在第1段或者第2段中的一段中出现,则将第3段估计的时偏值作为初始时偏值;如果同一个前导ID只在第3段出现,则比较3段和4段的SINR,取SINR大的那段序列估计出来的时偏值作为初始时偏值。Step 403, obtain initial time offset: obtain the initial time offset value through the joint judgment of the preamble ID result and SINR of each segment of parallel detection. Regardless of the detection results of paragraph 4: if the same leading ID is not only detected in paragraph 3, that is, it appears in paragraph 3 and at least one of paragraph 1 or paragraph 2, then the third paragraph is estimated If the same leading ID only appears in the third segment, compare the SINR of the third segment and the fourth segment, and take the estimated time offset value of the sequence with a larger SINR as the initial time offset value .

本实施例共4个用户路径时延分别为1000Ts(100KM以内),35000Ts(100~200KM以内),70000Ts(200KM~360KM)、80000Ts(超过360KM)。如图9所示,只看第1、第2和第3段的检测结果,用户1(时延为1000Ts)落在[0~24576)Ts内,在第1、第2和第3段都检测到该用户的前导ID0,将第3段估计的时偏值作为初始时偏值,时偏值为1000Ts;用户2(时延为35000Ts)落在[24576Ts~2*24576)Ts内,在第2和第3段都检测到该用户的前导ID1,将第3段估计的时偏值作为初始时偏值,时偏值为10424Ts;用户3(时延为70000Ts)落在[2*24576Ts~3*24576)Ts内,只在第3段检测到该用户的前导ID2,比较3段和4段的SINR,第4段的SINR大,取第4段估计出来的时偏值作为初始时偏值,时偏值为20848Ts;用户4(时延为80000Ts)超过3*24576Ts,在第1、2、3段峰值检测中都未出现前导ID3,用户4时偏过大超过该前导格式时偏范围,用户4随机接入失败。In this embodiment, a total of 4 user path delays are 1000Ts (within 100KM), 35000Ts (within 100-200KM), 70000Ts (200KM-360KM), and 80000Ts (over 360KM). As shown in Figure 9, only looking at the detection results of the first, second and third paragraphs, user 1 (with a delay of 1000Ts) falls within [0-24576) Ts, and the first, second and third paragraphs are all The leading ID0 of the user is detected, and the time offset value estimated in the third paragraph is used as the initial time offset value, and the time offset value is 1000Ts; The leading ID1 of the user is detected in both the 2nd and 3rd paragraphs, and the time offset value estimated in the 3rd paragraph is used as the initial time offset value, and the time offset value is 10424Ts; user 3 (with a delay of 70000Ts) falls in [2*24576Ts ~3*24576) Ts, only the leading ID2 of the user is detected in the third segment, compare the SINR of the third segment and the fourth segment, and the SINR of the fourth segment is larger, take the time offset value estimated in the fourth segment as the initial time Offset value, the time offset value is 20848Ts; user 4 (time delay is 80000Ts) exceeds 3*24576Ts, and the leading ID3 does not appear in the first, second, and third peak detection, and the time deviation of user 4 is too large to exceed the preamble format Out of range, user 4 fails in random access.

步骤404,进行校准:通过判断同一个前导ID在N+1个并行检测窗中出现的情况,分别进行不同的时偏校准,得到正确的时偏。Step 404, perform calibration: by judging the appearance of the same preamble ID in N+1 parallel detection windows, perform different time offset calibrations respectively to obtain the correct time offset.

在本实施例中,先不看第4段的检测结果,用户1的前导ID在第1段、第2段以及第3段3个并行峰值检测中都出现时,初始时偏值不需校准,初始时偏值作为最后上报的时偏值,即1000TS作为最后时偏值;用户2的前导ID在第1个峰值检测中未出现而在剩下的第2段和第3段峰值检测中出现时,将初始时偏值加上24576Ts得到35000TS的校准值,将校准值作为最后上报的时偏值;用户3的前导ID在第1和第2个峰值检测中未出现而在剩下的第3段峰值检测中出现时,将初始时偏值加上2*24576Ts得到校准值70000Ts,将校准值作为最后上报的时偏值;用户4的前导ID在前3个峰值检测中都未出现时,时延过大导致随机接入失败或者未发该前导ID。因此,在N=2情况下,使用该系统能检测的最大时偏范围为(2+1)*24576Ts=73728Ts,可覆盖半径为360KM。In this embodiment, regardless of the detection results of the fourth section, when the leading ID of user 1 appears in the three parallel peak detections of the first section, the second section, and the third section, the initial time offset value does not need to be calibrated , the initial time offset value is used as the last reported time offset value, that is, 1000TS is used as the last time offset value; the leading ID of user 2 does not appear in the first peak detection, but in the remaining second and third peak detections When it appears, add 24576Ts to the initial time offset value to get a calibration value of 35000TS, and use the calibration value as the last reported time offset value; When peak detection occurs in the third section, add 2*24576Ts to the initial time offset value to obtain a calibration value of 70000Ts, and use the calibration value as the last reported time offset value; the leading ID of user 4 does not appear in the first three peak detections When the time delay is too large, the random access fails or the preamble ID is not sent. Therefore, in the case of N=2, the maximum time offset range that can be detected by using this system is (2+1)*24576Ts=73728Ts, and the coverage radius is 360KM.

本发明实施例3:Embodiment 3 of the present invention:

在不改变LTERACH频域资源的情况下,以覆盖100KM小区为实施例,对本发明的发送方法和接收方法进行阐述。Under the condition of not changing the LTERACH frequency domain resource, the sending method and the receiving method of the present invention are described by taking the coverage of 100KM cell as an example.

本发明实施例3发送方法包括以下步骤:The sending method in Embodiment 3 of the present invention includes the following steps:

步骤201,按照如下方法配置RACH;Step 201, configure RACH according to the following method;

在不改变频域资源的情况下,此时要覆盖100KM的小区,本发明的发送方法为:首先计算N的大小,此时R=100Km,根据N的计算公式 得到N=0,由于N≥1,因此N取1,序列长度为24576Ts,CP长度为24576Ts,往返路径时延达到0.67ms,GT长度取0.67ms,则RACH总长度为2*24576Ts+0.67ms=1.6ms+0.67ms=2.27ms,总共需要3个TTI,由于总共占用3个TTI,因此将GT长度调整为1.4ms,因此100KM的覆盖格式和本发明中的实施例1中的200KM覆盖格式相同,如图6所示。In the case of not changing the frequency domain resources, at this time to cover a cell of 100KM, the transmission method of the present invention is: first calculate the size of N, at this time R=100Km, according to the calculation formula of N Get N=0, because N≥1, so N takes 1, the sequence length is 24576Ts, the CP length is 24576Ts, the round-trip path delay reaches 0.67ms, and the GT length takes 0.67ms, then the total length of RACH is 2*24576Ts+0.67ms =1.6ms+0.67ms=2.27ms, a total of 3 TTIs are needed, since a total of 3 TTIs are occupied, the GT length is adjusted to 1.4ms, so the coverage format of 100KM and the 200KM coverage format in Embodiment 1 of the present invention The same, as shown in Figure 6.

本前导格式需要的时频资源开销和LTE现有覆盖100KM的前导格式3相同,同时不需要改变频域位置,只改变时域上的RACH信号,对协议改动较小,更改起来方便,易于实现。The time-frequency resource overhead required by this preamble format is the same as that of the existing LTE preamble format 3 covering 100KM. At the same time, there is no need to change the frequency domain position, only the RACH signal in the time domain is changed. The protocol changes are small, and it is convenient to change and easy to implement. .

本发明设计的支持100KM的RACH前导格式比较灵活,可以采用本发明的接收方法(在实施例1中进行了详细阐述,此处不赘述),采用本发明的接收方法不仅实现了100KM覆盖还可以实现200KM覆盖,有效的扩大了系统的覆盖范围;亦可以采用传统的接收方法,采用传统接收方法可以实现和RACH现有格式3相同的100KM覆盖。对于本实施例因为只需要覆盖100KM,因此采用传统的检测方法即可。The RACH preamble format supporting 100KM designed by the present invention is relatively flexible, and the receiving method of the present invention (described in detail in Embodiment 1, which will not be described here) can be adopted. The receiving method of the present invention not only realizes 100KM coverage but also can 200KM coverage is achieved, which effectively expands the coverage of the system; traditional receiving methods can also be used, which can achieve the same 100KM coverage as the existing RACH format 3. For this embodiment, because it only needs to cover 100KM, the traditional detection method can be used.

由以上技术方案可以看出,本发明提供的一种提高覆盖能力的发送方法,是将CP和TSEQ都设计为以24576Ts为单位的序列或者序列重复,相比传统发送,本发明的RACH前导占用的时域资源更小。本发明将CP设计成24576Ts的固定长度,在序列部分为N个24576Ts的情况下,接收端利用CP和TSEQ序列重复的特点进行前导检测以及时偏校准,能够支持(N+1)*24576Ts的时偏,将系统可支持的时偏范围从受限于TSEQ长度的24576Ts大小扩大到(N+1)*24576Ts。It can be seen from the above technical solutions that a transmission method for improving coverage provided by the present invention is to design both CP and T SEQ as a sequence or sequence repetition in units of 24576Ts. Compared with traditional transmission, the RACH preamble of the present invention The occupied time domain resource is smaller. In the present invention, the CP is designed with a fixed length of 24576Ts. When the sequence part is N 24576Ts, the receiving end uses the characteristics of CP and T SEQ sequence repetition to perform preamble detection and time offset calibration, which can support (N+1)*24576Ts The time offset range that the system can support is expanded from 24576Ts limited by the length of T SEQ to (N+1)*24576Ts.

在本发明的发送方法下,本发明提供的提高覆盖能力的接收方法将包含CP在内的(N+1)*24576Ts长序列划分为以24576Ts为单位的N+1个处理序列,将它们分别进行峰值检测,通过对每段峰值检测的前导ID以及SINR的联合判决获得初始时偏值,并对初始时偏值进行校准,由于利用了24576Ts的CP长度以及TSEQ24576Ts重复的特点,该系统能支持的最大时偏范围从传统的24576Ts扩大为(N+1)*24576Ts。Under the sending method of the present invention, the receiving method for improving coverage provided by the present invention divides the (N+1)*24576Ts long sequence including CP into N+1 processing sequences with 24576Ts as the unit, and divides them into Perform peak detection, obtain the initial time offset value through the joint judgment of the preamble ID and SINR of each peak detection, and calibrate the initial time offset value. Due to the use of the CP length of 24576Ts and the characteristics of T SEQ 24576Ts repetition, the system The maximum time offset range that can be supported is expanded from the traditional 24576Ts to (N+1)*24576Ts.

在不增加频域资源的情况下,本发明提供的发送和接收方法能够通过占用较小的时域资源达到扩大系统覆盖范围的目的,对协议修改较小,减少开销,并且易于实现。Without increasing frequency domain resources, the sending and receiving method provided by the present invention can achieve the purpose of expanding system coverage by occupying less time domain resources, requires less protocol modification, reduces overhead, and is easy to implement.

尽管上文对本发明进行了详细说明,并举了实施例,但是本发明以及可应用的实施例不限于此,本技术领域技术人员可以根据本发明的原理进行各种修改。因此,凡按照本发明原理所作的修改,都应当理解为落入本发明的保护范围。Although the present invention has been described in detail above and examples have been given, the present invention and applicable embodiments are not limited thereto, and those skilled in the art can make various modifications according to the principle of the present invention. Therefore, any modifications made according to the principles of the present invention should be understood as falling within the protection scope of the present invention.

Claims (7)

  1. A kind of 1. accidental access signal method of sending and receiving applied to large coverage, it is characterised in that:Including following step Suddenly:
    User device configuration RACH RACH forms, the CP length of RACH forms, which is set, includes M repeatedly 24576Ts、TSEQLength is arranged to the 24576Ts of N number of repetition, wherein M=1, N >=1;N is by formulaR is covering scene radius, and C is the light velocity, and Ts=1/ (15000*2048) s is obtained;By The protection interval GT that RACH signals take length adjustment RACH signals is extremely more than or equal to trip path time delay;
    For RACH signals after user's setting send configuration to base station, base station extracts the peakvalue's checking sequence of N+2 sections 24576Ts length Row;N+2 section peakvalue's checking sequences are subjected to peakvalue's checking respectively;The targeting sequencing ID results and noise detected side by side to every section Bias when cascading judgement than SINR obtains initial;By judging that same targeting sequencing ID goes out in N+1 parallel detection window Existing situation, to it is initial when bias carry out calibration obtain correct targeting sequencing ID and when bias, accidental access signal receive into Work(.
  2. 2. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 1, its It is characterised by:The peakvalue's checking sequential extraction procedures process is:From the beginning the sequence extracted is divided successively backward with 24576Ts length For the 1st section, the section sequence of the 2nd section of N+2 section, parallel peakvalue's checking is carried out respectively to section sequence, records every section of peak value The targeting sequencing ID of detection and when bias and N+1 sections and N+2 sections detection window in SINR.
  3. 3. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 2, its It is characterised by:It is as follows to obtain process for bias when described initial:The testing result of the N+2 sections in section sequence is removed, when N+1 sections And at least one section in remaining N sections detects same preamble serial ID, then using N+1 section sequence estimations when bias as just The bias during beginning;The testing result of the N+2 sections in section sequence is removed, is occurred when same targeting sequencing ID in N+1 sections, then Compare the SINR of N+1 sections and N+2 sections, take that section of big sequence estimation of SINR come out when bias as it is initial when bias.
  4. 4. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 1, its It is characterised by:The N+2 sections peakvalue's checking sequence carries out peak-value detection method respectively:Every section of peakvalue's checking sequence frequency displacement is arrived At DC, sequence is filtered and down-sampling, obtains the sequence that length is 2048Ts, carry out 2048 point quick Fourier conversion, 839 point original ZC sequences are therefrom extracted, locally the frequency domain sequence of female code is total to the multiple of RACH frequency domain sequences received with ZC sequences Yoke is multiplied, and carries out 1536 points of inverse discrete Fourier transform, obtains PDP time domain correlations;PDP time domain correlations are taken into average, The setting of threshold value and the detection of peak value are carried out according to PDP averages, records the every section of targeting sequencing detected ID and corresponding When bias, calculate obtain SINR.
  5. 5. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 1, its It is characterised by:Bias calibration includes three kinds of modes when described:
    The first:Remove the testing result of N+2 sections, when same targeting sequencing ID in the parallel peakvalue's checking of preceding N+1 all During appearance, bias is not required to calibrate when initial, and bias is as the when bias finally reported when will be initial;
    Second:The testing result of N+2 sections is removed, when same targeting sequencing ID is at 1M (M=1N) When not occurring in individual peakvalue's checking, and occurring in remaining N+1-M peakvalue's checking, bias adds M* when will be initial 24576Ts obtains calibration value, using calibration value as the when bias finally reported;
    The third:The testing result of N+2 sections is removed, when same targeting sequencing ID does not occur in N+1 peakvalue's checking When, time delay is excessive to be caused random access failure or does not send out targeting sequencing ID.
  6. 6. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 1, its It is characterised by:The SINR value is the PDP peak energies in detection window and total PDP energy ratios.
  7. 7. a kind of accidental access signal method of sending and receiving applied to large coverage according to claim 6, its It is characterised by:The PDP peak energies are the energy that PDP peak maximums energy is nearby put plus peak value.
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