[liblo] Updating the example code for C++ programmers

Hi,

I looked at liblo for the first time today. I had some problems getting 
the example codes to run until I realized this is because of a subtle 
difference of C and C++. In 'example_server.c', line 82

lo_arg_pp(types[i], argv[i]);

(where types is of 'const char*') compiles nicely as C code using gcc. 
Using the same code from C++ however, compiling with g++, yields the 
following compiling error:

examples/example_server.c: In function ‘int generic_handler(const char*, 
const char*, lo_arg**, int, void*, void*)’:
examples/example_server.c:82:36: error: invalid conversion from ‘char’ 
to ‘lo_type’
examples/example_server.c:82:36: error: initializing argument 1 of ‘void 
lo_arg_pp(lo_type, void*)’

Researching I found this: In C, an enum (e.g. lo_type) is always of type 
int. Thus, an implicit type-cast is performed. In C++, enum is a 
distinct type and implicit conversion is not allowed. Making the cast 
explicit makes the code work in both C and C++, like so:

lo_arg_pp((lo_type) types[i], argv[i]);

Now I see that this is an example C code and maybe even a C++ programmer 
should be aware of that difference. But it's quite nasty so I'd suggest 
changing the example code to the above line or add a comment for naive 
C++ programmers like I am ;-)

I very much like liblo. It's very straightforward.
Regrads,
Jeremia